Average, Mixture and Alligation Question 1 - CAT 2022

Question

The average weight of students in a class increases by 600 gm when some new students join the class. If the average weight of the new students is 3 kg more than the average weight of the original students, then the ratio of the number of original students to the number of new students is:

  • A. 1 : 4
  • B. 1 : 2
  • C. 4 : 1
  • D. 3 : 1

Step-by-Step Explanation

This problem can be solved instantly using the Alligation Method by treating the weights as deviations from the original average weight.

  • Let the original average weight be W kg.
  • The average weight of the new students is W + 3 kg.
  • The combined average weight increases by 600 gm (0.6 kg), becoming W + 0.6 kg.

Set up the alligation cross-subtraction:

Original Students (W)  New Students (W + 3)

        /

        /

    Net (W + 0.6)

    /   

    /    

|(W + 3) βˆ’ (W + 0.6)|  |(W + 0.6) βˆ’ W|

= 2.4        = 0.6

The ratio of the number of original students to new students is:

Ratio = 2.4 : 0.6 = 4 : 1

Correct Option: C

πŸ’‘ FundaMakers Tip:

Bypassing long linear equations via Alligation saves massive amounts of time on average-based word problems. Simply look at the deviation: the new group brings an excess of 3 kg per student, but the class average only moves up by 0.6 kg. The ratio of the groups is always inversely proportional to their respective deviations from the mixture value.

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