Average, Mixture and Alligation Question 8 - CAT 2021
Identical chocolate pieces are sold in boxes of two sizes, small and large. The large box is sold for twice the price of the small box. If the selling price per gram of chocolate in the large box is 12% less than that in the small box, then the percentage by which the weight of chocolate in the large box exceeds that in the small box is nearest to:
Step-by-Step Explanation
Let the price of the small box be ₹100, and its chocolate weight be S grams.
Price of the large box = ₹200 (twice the small box).
Let the chocolate weight of the large box be L grams.
- Set up the unit price comparison per gram:
Price per gram (Small Box) = 100 / S
Price per gram (Large Box) = 200 / L
We are given that the unit price of the large box is 12% less than that of the small box:
200 / L = 0.88 × 100 / S
200 / L = 88 / S ⟹ L / S = 200 / 88 = 25 / 11
This ratio implies that for every 11 grams of chocolate in the small box, the large box contains 25 grams.
Percentage Excess = ((25 − 11) / 11) × 100%
= 14 / 11 × 100%
≈ 127.27%
The nearest integer value is 127%.
Correct Option: B
💡 FundaMakers Tip:
When handling commercial pricing models, remember the core structural relationship:
Weight = Total Price / Unit Cost.
Using the given adjustments, the weight ratio is:
L / S = Price Multiplier / Unit Cost Multiplier = 2 / 0.88 = 200 / 88
This shortcut eliminates the need to carry placeholder variables and isolates the percentage excess directly.