Profit and Loss Question 2 - CAT 2021

Question

Amal purchases some pens at ₹ 8 each. To sell these, he hires an employee at a fixed wage. He sells 100 of these pens at ₹ 12 each. If the remaining pens are sold at ₹ 11 each, then he makes a net profit of ₹ 300, while he makes a net loss of ₹ 300 if the remaining pens are sold at ₹ 9 each. The wage of the employee, in INR, is:

Step-by-Step Explanation

Let the total number of pens purchased be n.

Total Cost Incurred: CP = 8n + W, where W is the employee's fixed wage.

Now evaluate the two selling scenarios for the remaining n − 100 pens:

  • Scenario 1 (Remaining sold at ₹ 11):

Total SP₁ = 100 × 12 + 11(n − 100) = 1200 + 11n − 1100 = 11n + 100

Profit = SP₁ − CP = 300

11n + 100 − 8n − W = 300

3n − W = 200 --- (Equation 1)

  • Scenario 2 (Remaining sold at ₹ 9):

Total SP₂ = 100 × 12 + 9(n − 100) = 1200 + 9n − 900 = 9n + 300

Loss = CP − SP₂ = 300

8n + W − 9n − 300 = 300

W − n = 600 --- (Equation 2)

Add Equation 1 and Equation 2 together to eliminate W:

(3n − W) + (W − n) = 200 + 600

2n = 800

n = 400 pens

Substitute n = 400 back into Equation 2 to find the wage:

W − 400 = 600

W = 1000

The fixed wage of the employee is ₹ 1000.

Correct Answer: 1000

💡 FundaMakers Tip:

Look at the variance between the two situations. The cost price structure and the first 100 pens sold are completely identical in both cases. The only difference is that the remaining pens are sold for ₹ 11 instead of ₹ 9—a difference of ₹ 2 per pen.

This change shifts the merchant's final position from a ₹ 300 profit to a ₹ 300 loss—a net variance of ₹ 600.

Remaining Pens × 2 = 600

Remaining Pens = 300

Total pens n = 300 + 100 = 400.

Analyzing the delta saves you from writing out full algebraic setups.

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