Averages , Ratio and Proportion Question 6 - CAT 2022

Question

The average of three integers is 13. When a natural number n is included, the average of these four integers remains an odd integer. The minimum possible value of n is:

  • A. 3
  • B. 4
  • C. 5
  • D. 1

Step-by-Step Explanation

  • Set up the aggregate sum equation:

The average of three integers is 13, so their sum is:

13 × 3 = 39

When a natural number n is added, the new average across all 4 numbers becomes:

New Average = (39 + n)/4

  • Apply the odd integer constraint:

Let this new average be an odd integer k:

(39 + n)/4 = k

39 + n = 4k

n = 4k − 39

  • Find the minimum value:

Since n must be a natural number (n ≥ 1):

4k − 39 ≥ 1

4k ≥ 40

k ≥ 10

The smallest odd integer that satisfies k ≥ 10 is k = 11.

n minimum = 4(11) − 39 = 44 − 39 = 5

Correct Option: C

💡 FundaMakers Tip:

Work forward from the constraints on the average. Since the sum of the first three numbers is 39, the next total value must be a multiple of 4 (40, 44, 48, …). Dividing 40 by 4 gives an even average (10), while dividing 44 by 4 gives an odd average (11). This reveals that 39 + n = 44, so n = 5 almost instantly.

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